Project Euler: Problem 6

By | 17. April 2013

The sum of the squares of the first ten natural numbers is,
12 + 22 + … + 102 = 385
The square of the sum of the first ten natural numbers is,
(1 + 2 + … + 10)2 = 552 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

long result = 0;
long sum1 = 0;
long sum2 = 0;
for (int i=1; i<=100; i++) {
	sum1 += (long)Math.pow(i,2);
	sum2 += i;
}
result = (long)Math.pow(sum2, 2)-sum1;
System.out.println(result);

Lösung: 25164150

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