Project Euler: Problem 48

The series, 1¹ + ²² + ³³ + … + 10¹⁰ = 10405071317.

Find the last ten digits of the series, 1¹ + 2² + 3³ + … + 1000¹⁰⁰⁰.

BigInteger number = BigInteger.ONE;
BigInteger result = BigInteger.ZERO;
 
for (long i = 1; i <=1000; i++) {
	number = BigInteger.valueOf(i);
	result = result.add(number.pow((int)i));
}
String output = result.toString();
System.out.println(output.substring(output.length()-10));

Lösung: 9110846700